Duration: 4:51

0 views

0

A velocity filter uses the properties of electric and magnetic field to select particles that are moving with a specific velocity. Charged particles with varying speeds are directed into the filter
as shown. The filter consists
of an electric field \( E \) and a
magnetic field \( B \), each of constant
magnitude, directed perpendicular
to each other as shown. The charge
particles will experience a force
due to electric field given by \( F= \)
\( q E \). If positively charged particles
are used, this force is towards right.
The moving particle will also experience a force due to magnetic field given by \( F=q v B \). When forces due to the two fields are of equal magnitude, the net force on the particle will be zero, the particle will pass through centre with its path unaltered. The electric and magnetic fields can be adjusted to choose the specific velocity to be filtered. The effect of gravity can be neglected.
The electric and magnetic fields are adjusted to detect particles with positive charge \( q \) of certain speed \( v_{0} \). Which of the following expressions is equal to this speed?
(1) \( \frac{B}{q^{2} E} \)
(2) \( \left(\frac{E}{q^{2} B}\right) \)
(3) \( \left(\frac{B}{E}\right) \)
(4) \( \left(\frac{E}{B}\right) \)
📲PW App Link - https://bit.ly/YTAI_PWAP
🌐PW Website - https://www.pw.live