ABC is a triangle with \( \angle \mathrm{B}=2 \angle \mathrm{C} \). D is a point on \( \mathrm{B...
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ABC is a triangle with \( \angle \mathrm{B}=2 \angle \mathrm{C} \). D is a point on \( \mathrm{BC} \) such that \( \mathrm{AD} \) bisects \( \angle \mathrm{BAC} \) and \( A B=C D \). Prove that \( \angle B A C=72^{\circ} \).
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