According to Gauss's theorem in electrostatics, total electric flux...

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According to Gauss's theorem in electrostatics, total electric flux over a closed surface \( S \) in vacuum is \( 1 / \epsilon_{0} \) times the total charge \( (Q) \) contained inside \( S \)
i.e., \( \phi_{E}=\oint_{s s} \vec{E} \cdot d \vec{s}=\frac{Q}{\epsilon_{0}} \)
The charges enclosed may be distributed any way. If the medium surrounding the charge has a dielectric constant \( K \). then
\[
\phi_{E}=\frac{Q}{\epsilon}=\frac{Q}{K \epsilon_{0}}
\]
Charges situated outside the surface make no contribution to electric flux.

Charges \( +6 q,-2 q \) and \( +3 q \) are enclosed by a surface in vacuum. The total electric flux over the surface is
(a) \( 6 q / \epsilon_{0} \)
(b) \( -2 q / \epsilon_{0} \)
(c) \( \frac{3 q}{\epsilon_{0}} \)
(d) \( 7 q / \epsilon_{0} \)
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