Adding powdered \( \mathrm{Pb} \) and \( \mathrm{Fe} \) to a solution containing \( 1.0 \mathrm{...

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Adding powdered \( \mathrm{Pb} \) and \( \mathrm{Fe} \) to a solution containing \( 1.0 \mathrm{M} \) each of \( \mathrm{Pb}^{2+} \) and \( \mathrm{Fe}^{2+} \) ions would result into the formation of
(a) More of \( \mathrm{Pb} \) and \( \mathrm{Fe}^{2+} \) ions
(b) More of \( \mathrm{Fe} \) and \( \mathrm{Pb}^{2+} \) ions
(c) More of \( \mathrm{Fe} \) and \( \mathrm{Pb} \)
(d) More of \( \mathrm{Fe}^{2+} \) and \( \mathrm{Pb}^{2+} \) ions
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