An \( \alpha \)-particle accelerated through \( V \) volt is fired ...

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An \( \alpha \)-particle accelerated through \( V \) volt is fired
\( \mathrm{P} \) towards a nucleus. It's distance of closest approach is

W. \( r \). If a proton accelerated through the same potential is fired towards the same nucleus, the distance of closest approach of the proton will be
(1) \( r \)
(2) \( 2 r \)
(3) \( r / 2 \)
(4) \( r / 4 \)
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