An object undergoing simple harmonic motion takes \( 0.25 \mathrm{~s} \) to travel from one poin... VIDEO
An object undergoing simple harmonic motion takes \( 0.25 \mathrm{~s} \) to travel from one point of zero velocity to the next such point. The distance between those points is \( 32 \mathrm{~cm} \). Calculate the (a) period, (b) frequency, and (c) amplitude of the motion.https://bit.ly/YTAI_PWAP https://www.pw.live
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