Assuming that Earth and mars move in circular orbits around the sun, with the martian orbit bein....

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Assuming that Earth and mars move in circular orbits
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around the sun, with the martian orbit being 1.52 times the orbital radius of the Earth. The length of the
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martian year in days is
(1) \( (1.52)^{2 / 3} \times 365 \)
(2) \( (1.52)^{3 / 2} \times 365 \)
(3) \( (1.52)^{2} \times 365 \)
(4) \( (1.52)^{3} \times 365 \)


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