Minimum Number of Days to Make m Bouquets | Simple Thought Process| Leetcode 1482 | codestorywithMIK
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This is the 29th Video of our Playlist "Binary Search : Popular Interview Problems" by codestorywithMIK
In this video we will try to solve a very good and famous Problem on Binary Search on Answer topic : Minimum Number of Days to Make m Bouquets | Simple Thought Process | Leetcode 1482 | codestorywithMIK
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Problem Name : Minimum Number of Days to Make m Bouquets | Simple Thought Process | Leetcode 1482 | codestorywithMIK
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Summary :
getNumOfBouquets Method:
This method calculates how many bouquets can be made by the mid day.
It iterates through bloomDay to count consecutive flowers that can be picked, forming bouquets when k consecutive flowers are found.
minDays Method:
This method uses binary search to find the minimum day (minDays) by which m bouquets can be made.
It initializes startDay to 1 (assuming 0 is not a valid day) and endDay to the maximum value in bloomDay.
In the binary search loop, it calculates mid and uses getNumOfBouquets to check if at least m bouquets can be made by mid day.
If m bouquets can be made, it updates minDays and adjusts endDay to search for potentially smaller valid days.
If not, it adjusts startDay to search for larger valid days.
Edge Case Handling:
If there are not enough flowers to make m bouquets, it returns -1 immediately.
Usage
The main method provides an example usage of the Solution class to test the minDays method.
By following this structure, we ensure the solution remains efficient and easy to understand.
✨ Timelines✨
00:00 - Introduction
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