\[ \begin{array}{l} \text { If }(\sec A+\tan A)(\sec B+\tan B)(\sec C+\tan C) \\ =(\sec A-\tan A...

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\[
\begin{array}{l}
\text { If }(\sec A+\tan A)(\sec B+\tan B)(\sec C+\tan C) \\
=(\sec A-\tan A)(\sec B-\tan B)(\sec C-\tan C)
\end{array}
\]
then prove that each side of the given equation is \pm 1 .
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