Butane exists in various conformations in nature. At any given instant, the probability that a g...
0Butane exists in various conformations in nature. At any given instant, the probability that a given butane molecule is in anti, gauche, eclipsed and fully eclipsed conformation is \( 0.7,0.2,0.06 \) and \( 0.04 \), respectively. If the molar enthalpy of combustion of natural butane is \( -690 \mathrm{kcal} / \mathrm{mol} \) at \( 25^{\circ} \mathrm{C} \), then calculate the enthalpy of combustion of butane if all the butane molecules are in gauche conformation. The potential energy of gauche form is \( 2 \mathrm{kcal} / \mathrm{mol} \) higher than anti form but it is \( 3 \mathrm{kcal} / \mathrm{mol} \) less than eclipsed form and \( 5.5 \mathrm{kcal} / \mathrm{mol} \) less than fully eclipsed form.
(a) \( -690 \mathrm{kcal} / \mathrm{mol} \)
(b) \( -689 \mathrm{kcal} / \mathrm{mol} \)
(c) \( -691 \mathrm{kcal} / \mathrm{mol} \)
(d) \( -692 \mathrm{kcal} / \mathrm{mol} \)
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