C++ : Does initialization entail lvalue-to-rvalue conversion? Is `int x = x;` UB?
C++ : Does initialization entail lvalue-to-rvalue conversion? Is `int x = x;` UB?
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C++ : Does initialization entail lvalue-to-rvalue conversion? Is `int x = x;` UB?
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initialization x : lvalue-to-rvalue = Is UB? conversion? `int x;` Does entail C++