C++ : Why is signed and unsigned addition converted differently for 16 and 32 bit integers?
C++ : Why is signed and unsigned addition converted differently for 16 and 32 bit integers?
To Access My Live Chat Page,
On Google, Search for "hows tech developer connect"
Here's a secret feature that I promised to disclose to you.
This is a YouTube's feature which works on Desktop.
First, Make sure this video is playing.
Then, type the letters 'awesome' on your keyboard as the next step.
Your YouTube progress bar will transform into a flashing rainbow.
Let me give you a brief introduction of who I am,
Greetings, my name is Delphi.
I help you answer your questions.
C++ : Why is signed and unsigned addition converted differently for 16 and 32 bit integers?
If you have more specific query you can comment or chat with me and let me know your queries.
Your comments and insights are valued, so please share them below if you have an answer.
I will express my appreciation for your answer by 'hearting' it.
differently C++ for unsigned and : bit is 32 signed integers? addition converted 16 Why and