Duration: 6:06

4 views

0

Calculate the Gibb's energy change when 1 mole of
P \( \mathrm{NaCl} \) is dissolved in water at \( 25^{\circ} \mathrm{C} \). Lattice energy of

W \( \mathrm{NaCl}=777.8 \mathrm{~kJ} \mathrm{~mol}^{-1} ; \Delta \mathrm{S} \) for dissolution \( =0.043 \) \( \mathrm{kJ} \mathrm{mol}{ }^{-1} \) and hydration energy of \( \mathrm{NaCl}=-774.1 \mathrm{~kJ} \) \( \mathrm{mol}^{-1} \).
(1) \( -9.114 \mathrm{~kJ} \mathrm{~mol}=-1 \) (2) \( -11.4 \mathrm{~kJ} \mathrm{~mol}^{-1} \)
(3) \( -5.4 \mathrm{~kJ} \mathrm{~mol}^{-1} \)
(4) \( -4.5 \mathrm{~kJ} \mathrm{~mol}^{-1} \)
📲PW App Link - https://bit.ly/YTAI_PWAP
🌐PW Website - https://www.pw.live