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Calculate the potential for half cell containing:
\( 0.10 \mathrm{M} \mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7} \) (aq), \( 0.20 \mathrm{M} \mathrm{Cr}^{3+}(\mathrm{aq}) \) and \( 1.0 \times 10^{-4} \mathrm{M} \mathrm{H}^{+}(\mathrm{aq}) \)
\( \mathrm{P} \) The half cell reaction is

W \( \mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}(\mathrm{aq})+14 \mathrm{H}^{+}(\mathrm{aq})+6 \mathrm{e}^{-} \rightarrow 2 \mathrm{Cr}^{3+}(\mathrm{aq})+7 \mathrm{H}_{2} \mathrm{O}(l) \) and the standard electrode potential is given as \( \mathrm{E}^{0}=1.33 \mathrm{~V} \)
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