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Calculate the potential of an indicator electrode versus the standard hydrogen electrode, which originally contained 0.1 \( \mathrm{M} \mathrm{MnO}_{4}^{-} \)and \( 0.8 \mathrm{M} \mathrm{H}^{+} \)and which was treated with \( \mathrm{Fe}^{2+} \) necessary to reduce \( 90 \% \) of the \( \mathrm{MnO}_{4}^{-} \)to \( \mathrm{Mn}^{+2} \).
\[
\mathrm{MnO}_{4}^{-}+8 \mathrm{H}^{+}+5 \mathrm{e}^{-} \rightarrow \mathrm{Mn}^{2+}+4 \mathrm{H}_{2} \mathrm{O}, \mathrm{E}^{\mathrm{o}}=1.51 \mathrm{~V}
\]
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