Consider the non-zero vectors \( \vec{a}, \vec{b}, \vec{c} \) and \( \vec{d} \) such that no thr...

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Consider the non-zero vectors \( \vec{a}, \vec{b}, \vec{c} \) and \( \vec{d} \) such that no three of which are coplanar then prove that \( \vec{a}[\vec{b} \vec{c} \vec{d}]+\vec{c}[\vec{a} \vec{b} \vec{d}] \) \( =\vec{b}[\vec{a} \vec{c} \vec{d}]+\vec{d}[\vec{a} \vec{b} \vec{c}] \). Hence prove that if \( \vec{a}, \vec{b}, \vec{c} \) and \( \vec{d} \) represent the position vectors of the vertices of a plane quadrilateral then \( \frac{[\vec{b} \vec{c} \vec{d}]+[\vec{a} \vec{b} \vec{d}]}{[\vec{a} \vec{c} \vec{d}]+[\vec{a} \vec{b} \vec{c}]}=1 \)
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