Consider two circles \( x^{2}+y^{2}=1 \) and \( (x-1)^{2}+(y-1)^{2}=3 \) then the point circle w...

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Consider two circles \( x^{2}+y^{2}=1 \) and \( (x-1)^{2}+(y-1)^{2}=3 \)
then the point circle which is orthogonal to the given two circles can be
(a) \( \left(x-\frac{1}{2}\right)^{2}+\left(y-\frac{1}{2}\right)^{2}=0 \)
(b) \( \left(x-\frac{1}{\sqrt{2}}\right)^{2}+\left(y-\frac{1}{\sqrt{2}}\right)^{2}=0 \)
(c) \( (x-1)^{2}+(y-1)^{2}=0 \)
(d) \( (x-1)^{2}+(y+1)^{2}=0 \)
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