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Construct a triangle \( \mathrm{ABC} \) in which \( \mathrm{BC}=7 \mathrm{~cm}, \angle \mathrm{B}=75^{\circ} \) and \( \mathrm{AB}+\mathrm{AC}=13 \mathrm{~cm} \).
Ans fteps of construction:
(i) Draw a line segment \( B C=7 \mathrm{~cm} \).
(ii) At B, draw \( \angle C B X=75^{\circ} \)
(iii) iet a line segment \( B D=13 \mathrm{~cm} \) from \( B X \).
(iv) Join \( D C \)
(v) Draw the perpendicular bisector LM of CD, which intersect BD at \( A \) -
(vi) Join \( A C \). Then \( A B C \) is the required triangle.
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