Divisible and Non-divisible Sums Difference | Constant Time | Leetcode 2894 | codestorywithMIK
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Hi Everyone, this is the 90th video of our Playlist "Leetcode Easy".
Now we will be solving an easy Problem based on Maths - Divisible and Non-divisible Sums Difference | Constant Time | Maths Derivation | Leetcode 2894 | codestorywithMIK
I will explain it in full detail so that it becomes easy to understand. We will find the reason behind everything so that we understand why we did what we did.
And we will do a complete dry run.
Problem Name : Divisible and Non-divisible Sums Difference | Constant Time | Maths Derivation | Leetcode 2894 | codestorywithMIK
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Code Github(C++ & JAVA) : https://github.com/MAZHARMIK/Interview_DS_Algo/blob/master/Mathematical/Divisible and Non-divisible Sums Difference.cpp
Leetcode Link : https://leetcode.com/problems/divisible-and-non-divisible-sums-difference
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Video Summary :
The solution leverages mathematical formulas to efficiently compute the required sums without iteration.
Calculate the total sum from 1 to n using the formula n*(n+1)/2.
Compute the sum of numbers divisible by m using the formula for an arithmetic series: m * k * (k+1) / 2, where k = n / m.
Subtract the divisible sum from the total sum to get num1 - num2 as required.
✨ Timelines✨
00:00 - Introduction
0:13 - Motivation
0:36 - Problem Explanation
2:05 - Constant Time Explanation
3:09 - Mathematical Derivation
10:41 - Coding it up
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