Zero Array Transformation I | Brute Force | Optimal | Leetcode 3356 | codestorywithMIK

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Hi Everyone, this is the 4th video of our Playlist "Difference Array Technique: Concepts & Qns".
Now we will be solving a very a good problem on already studied concept on "Difference Array Technique: Concepts & Qns" -
Zero Array Transformation I | Brute Force | Optimal | Leetcode 3356 | codestorywithMIK

We will start from Super Brute Force and then to Better Brute Force using Difference Array Technique and then we will move to Optimal Approach using Difference Array Technique.

Problem Name : Zero Array Transformation I | Brute Force | Optimal | Leetcode 3356 | codestorywithMIK
Company Tags : will update later
My solutions on Github(C++ & JAVA) : https://github.com/MAZHARMIK/Interview_DS_Algo/blob/master/Arrays/Difference Array Technique/Zero Array Transformation I.cpp
Leetcode Link : https://leetcode.com/problems/zero-array-transformation-i


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Difference Array Technique: Concepts & Qns :    • Introduction | What | How | Differenc...  
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Video Summary :
Approach 1 (Simple Simulation):
This approach applies each query one by one on the array and once all queries are done , we check in the last if the input array has become all zero or not.

Approach 2 (Binary Search on Queries using Difference Array):
The problem uses a range update optimization with a difference array to efficiently track the number of operations applied across subarrays. Each query adds a +1 increment over a given range, and we build a diff array to record these in constant time per query. We then compute the cumulative sum to find how many operations affect each index. Finally, we check if the number of applied operations is sufficient to reduce each nums[i] to zero. If any element needs more operations than available, we return false.



✨ Timelines✨
00:00 - Introduction
0:09 - Motivation
0:32 - Problem Explanation
3:52 - Brute Force
5:47 - Optimal : Why Difference Array Technique
7:38 - Dry Run Step-1 and Step-2 of Difference Array Technique
15:44 - Coding it up

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