Draw a triangle \( \mathrm{ABC} \) with side \( \mathrm{BC}=7 \mathrm{~cm}, \angle \mathrm{B}=45^{\circ}, \angle \mathrm{A}=105^{\circ} \). Then, construct a triangle whose sides are \( \frac{4}{3} \) times the corresponding sides of \( \triangle \mathrm{ABC} \).
Fs: Stept of Contruction:
(1) Draw a line segment \( B C=7 \mathrm{~cm} \)
(2) Draw \( \angle A B C=45^{\circ} \) and \( \angle A C B=30^{\circ} \) i.e. \( \angle B A C=105^{\circ} \)
(3) We get \( \triangle A B C \)
(4) Draw a ray BX making an angle with
(5) Mark four poines \( B_{4}, B_{2}, B_{3}, B_{4} \) on \( B X \) such that \( B B_{2}=B_{1} B_{2}=B_{2} B_{3}=B_{3} B_{4} \)
(6) \( \operatorname{Iin} B_{3} C \)
(7) Trroagh \( B_{4} \) draw a line \( B_{4} C^{1} 11 B_{3} C_{\text {i intersecting the }} \)
\( I_{1} i_{1}^{+} \cdot \) extended line \( B C \) at \( C^{\prime} \)
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