Each of the two strings of length \( 51.6 \mathrm{~cm} \) and \( 49...

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Each of the two strings of length \( 51.6 \mathrm{~cm} \) and \( 49.1 \mathrm{~cm} \) are tensioned separately by \( 20 \mathrm{~N} \) force. Mass per unit length of both the strings is same and equal to \( 1 \mathrm{~g} / \mathrm{m} \). When both the strings vibrate simultaneously the number of beats is
\( \mathrm{P} \)
[CBSE PMT 2009]
(a) 5
(b) 7
(c) 8
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