Find the Length of the Longest Common Prefix | 2 Approaches | Leetcode 3043 | codestorywithMIK
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This is the 6th Video of our Playlist "TRIE : Popular Interview Problems" by codestorywithMIK
In this video we will try to solve a classic Trie problem : Find the Length of the Longest Common Prefix | 2 Approaches | Trie | Leetcode 3043 | codestorywithMIK
I will explain the intuition so easily that you will never forget and start seeing this as cakewalk EASYYY.
We will do live coding after explanation and see if we are able to pass all the test cases.
Also, please note that my Github solution link below contains both C++ as well as JAVA code.
Problem Name : Find the Length of the Longest Common Prefix | 2 Approaches | Trie | Leetcode 3043 | codestorywithMIK
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Summary :
Approach 1 - Brute Force:
In this approach, we store all possible prefixes of the numbers from the first array (arr1) into a set. A number's prefixes are formed by repeatedly removing the last digit until it becomes zero. Then, for each number in the second array (arr2), we reduce it similarly by removing digits until a match is found in the set. The length of the matched prefix is calculated using log10 to count digits, and the longest common prefix length is tracked.
Time Complexity: O(m⋅log10M + n⋅log10N)
Space Complexity: O(m⋅log10M)
Approach 2 - Using Prefix Tree (Trie):
This approach builds a trie (prefix tree) from the numbers in the first array (arr1), where each digit forms a node. For each number in the second array (arr2), we traverse the trie to find the longest matching prefix by comparing digits. The length of the matched prefix is returned, and we track the maximum prefix length across all numbers in arr2.
Time Complexity: O(m⋅d + n⋅d)
Space Complexity: O(m⋅d)
Where m and n are the lengths of arr1 and arr2, and d is the average number of digits in the numbers.
✨ Timelines✨
00:00 - Introduction
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