Different Ways to Add Parentheses | Simple Story To Code | Leetcode 241 | codestorywithMIK
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This is the 5th Video of our Playlist "Recursion : Popular Interview Problems" by codestorywithMIK
In this video we will try to solve a standard Recursion problem : Different Ways to Add Parentheses | Simple Story To Code | Leetcode 241 | codestorywithMIK
I will explain the intuition so easily that you will never forget and start seeing this as cakewalk EASYYY.
We will do live coding after explanation and see if we are able to pass all the test cases.
Also, please note that my Github solution link below contains both C++ as well as JAVA code.
Problem Name : Different Ways to Add Parentheses | Simple Story To Code | Leetcode 241 | codestorywithMIK
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Summary :
The approach uses a divide-and-conquer strategy to compute all possible results from a mathematical expression by inserting parentheses in different ways. The expression is recursively split at each operator (+, -, *), with the left and right substrings being evaluated separately. The results from the left and right sides are then combined based on the operator between them. If no operator is found, the substring is treated as a number.
The function recursively breaks the expression until base cases (numbers) are reached, and results are combined at each step. This results in multiple recursive calls, generating all possible outcomes of the expression.
Key Idea:
Recursively split the expression at each operator.
Evaluate and combine results from left and right subexpressions.
Base case: if the string is a number, return it as a result.
This approach leads to an exponential number of recursive calls due to the multiple ways to split the expression.
✨ Timelines✨
00:00 - Introduction
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