Divide Players Into Teams of Equal Skill | With Proof | Dry Run | Leetcode 2491 | codestorywithMIK
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This is the 113th Video of our Playlist "Array 1D/2D : Popular Interview Problems" by codestorywithMIK
In this video we will try to solve a good Array Practice Problem : Divide Players Into Teams of Equal Skill | With Proof | Full Dry Run | Leetcode 2491 | codestorywithMIK
I will also show the proof on why we select lowest number to highest number, second lowest to second largest and so on.
I will explain the intuition so easily that you will never forget and start seeing this as cakewalk EASYYY.
We will do live coding after explanation and see if we are able to pass all the test cases.
Also, please note that my Github solution link below contains both C++ as well as JAVA code.
Problem Name : Divide Players Into Teams of Equal Skill | With Proof | Full Dry Run | Leetcode 2491 | codestorywithMIK
Company Tags : will soon update
My solutions on Github(C++ & JAVA) - https://github.com/MAZHARMIK/Interview_DS_Algo/blob/master/Arrays/Divide Players Into Teams of Equal Skill.cpp
Leetcode Link : https://leetcode.com/problems/divide-players-into-teams-of-equal-skill
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Summary :
Approach 1: Two Pointers with Sorting
Steps:
Sort the skill array.
Use two pointers (i starting from the beginning and j from the end) to form pairs.
Calculate the sum of each pair (skill[i] + skill[j]) and check if it matches a precomputed sum.
If any pair doesn't match, return -1.
Calculate and accumulate the chemistry (skill[i] * skill[j]) for each valid pair.
Complexity:
Time Complexity: O(nlogn) due to sorting.
Space Complexity: O(1) extra space (ignoring the input array).
Use Case:
Efficient when the sum constraints are simple and the array can be sorted easily.
Approach 2: Frequency Array with Target Sum
Steps:
Use a frequency array (freq) to track occurrences of each skill.
Calculate the total sum of the skills and determine the target sum for each team.
For each skill, find its complementary skill (target - skill[i]) using the frequency array.
If the complementary skill is not present, return -1.
Accumulate chemistry (skill[i] * complementarySkill) and adjust frequencies.
Complexity:
Time Complexity: O(n) (linear traversal).
Space Complexity: O(1001) for the frequency array.
Use Case:
Useful when the input values have a constrained range, allowing quick frequency lookups.
✨ Timelines✨
00:00 - Introduction
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