Minimum Time Difference | Easy Approach | Detailed | Leetcode 539 | codestorywithMIK

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This is the 109th Video of our Playlist "Array 1D/2D : Popular Interview Problems" by codestorywithMIK

In this video we will try to solve a good Array Problem with Bit Magic Property : Minimum Time Difference | Easy Approach | Detailed | Leetcode 539 | codestorywithMIK

I will explain the intuition so easily that you will never forget and start seeing this as cakewalk EASYYY.
We will do live coding after explanation and see if we are able to pass all the test cases.
Also, please note that my Github solution link below contains both C++ as well as JAVA code.

Problem Name : Minimum Time Difference | Easy Approach | Detailed | Leetcode 539 | codestorywithMIK
Company Tags : Palantir Technologies, META, Palantir
My solutions on Github(C++ & JAVA) - https://github.com/MAZHARMIK/Intervie...
Leetcode Link : https://leetcode.com/problems/minimum...


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Summary :
The given approach to solving the problem of finding the minimum time difference between time points follows these steps:

Convert Time to Minutes: The input times are in HH:MM format. For each time string in the timePoints vector, the algorithm extracts the hours and minutes, converts them to integers, and then calculates the total minutes since midnight. These minute values are stored in a separate vector, minutes.

Sort the Minutes: The minutes vector is sorted to facilitate easy comparison of adjacent time points.

Find Minimum Difference: After sorting, the minimum time difference between consecutive times is calculated. A loop runs through the sorted list, comparing the difference between each pair of adjacent times.

Handle Circular Time: To account for the circular nature of the clock (e.g., the difference between 23:59 and 00:00), the algorithm also compares the difference between the last and the first time point across midnight.

Return the Result: The smallest difference found is returned as the result.

This approach ensures that the minimum time difference is efficiently found using sorting and simple comparisons. The time complexity is dominated by the sorting step, making it O(n log n).


✨ Timelines✨
00:00 - Introduction


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