\( \frac{\sin 3 \theta}{2 \cos 2 \theta+1}=\frac{1}{2} \) if (A) \( \theta=2 n \pi+\frac{\pi}{6}...
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\( \frac{\sin 3 \theta}{2 \cos 2 \theta+1}=\frac{1}{2} \) if
(A) \( \theta=2 n \pi+\frac{\pi}{6} \)
(B) \( \theta=n \pi+(-1)^{n} \frac{\pi}{6} \)
(C) \( \theta=2 n \pi-\frac{\pi}{6} \)
(D) \( \theta=n \pi-\frac{\pi}{6} \)
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