Gene A and B are linked and 12 map units apart. A heterozygous individual, whose parents were AA...
Channel:
Subscribers:
447,000
Published on ● Video Link: https://www.youtube.com/watch?v=zCoqNnsd3SE
Gene A and B are linked and 12 map units apart. A heterozygous individual, whose parents were AAbb and aaBB, would be expected to produce gamete in the following frequencies -
(a) \( 44 \% \mathrm{AB}, 6 \% \mathrm{Ab}, 6 \% \mathrm{aB}, 44 \% \) ab
(b) \( 6 \% \mathrm{AB}, 44 \% \mathrm{Ab}, 44 \% \mathrm{aB}, 6 \% \) ab
(c) \( 12 \% \mathrm{AB}, 38 \% \mathrm{Ab}, 38 \% \mathrm{aB}, 12 \% \) ab
(d) \( 6 \% \mathrm{AB}, 6 \% \mathrm{Ab}, 44 \% \mathrm{aB}, 44 \% \mathrm{ab} \)
ЁЯУ▓PW App Link - https://bit.ly/YTAI_PWAP
ЁЯМРPW Website - https://www.pw.live