If \( A=\left(\begin{array}{lll}1 & 4 & 0 \\ 5 & 2 & 6 \\ 1 & 7 & 1...

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If \( A=\left(\begin{array}{lll}1 & 4 & 0 \\ 5 & 2 & 6 \\ 1 & 7 & 1\end{array}\right) \& A^{-1}=\frac{1}{36}\left(\alpha A+\beta A^{2}+\gamma I\right) \), then
P
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\( \frac{|\alpha+\beta+\gamma|}{3} \) is equal to \( P \), then sum of digit of \( P \) will be (where \( I \) is identity matrix)
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