If \( \arg (z+a)=\frac{\pi}{6} \) and \( \arg (z-a)=\frac{2 \pi}{3}\left(a \in R^{+}\right) \), ...
If \( \arg (z+a)=\frac{\pi}{6} \) and \( \arg (z-a)=\frac{2 \pi}{3}\left(a \in R^{+}\right) \), then
(a) \( |z|=a \)
(b) \( |z|=2 a \)
(c) \( \arg (z)=\frac{\pi}{3} \)
(d) \( \arg (z)=\frac{\pi}{2} \)
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