If \( f(x)=\frac{1-\sin x}{(\pi-2 x)^{2}} \), when \( x \neq \frac{...

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If \( f(x)=\frac{1-\sin x}{(\pi-2 x)^{2}} \), when \( x \neq \frac{\pi}{2} \) and \( f\left(\frac{\pi}{2}\right)=\lambda \), then \( f(x) \) will be continuous function at \( x=\pi / 2 \), where \( \lambda= \)
(a) \( 1 / 8 \)
(b) \( 1 / 4 \)
(c) \( 1 / 2 \)
(d) none of these
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