If light of wavelength \( \lambda_{1} \) is allowed to fall on a metal, then kinetic energy of p...

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If light of wavelength \( \lambda_{1} \) is allowed to fall on a metal, then kinetic energy of photoelectrons emitted is \( E_{1} \). If wavelength of light changes to \( \lambda_{2} \) then kinetic energy of electrons changes to \( E_{2} \). Then work function of the metal is
(A) \( \frac{E_{1} E_{2}\left(\lambda_{1}-\lambda_{2}\right)}{\lambda_{1} \lambda_{2}} \)
(B) \( \frac{E_{1} \lambda_{1}-E_{2} \lambda_{2}}{\left(\lambda_{1}-\lambda_{2}\right)} \)
(C) \( \frac{E_{1} \lambda_{1}-E_{2} \lambda_{2}}{\left(\lambda_{2}-\lambda_{1}\right)} \)
(D) \( \frac{\lambda_{1} \lambda_{2} E_{1} E_{2}}{\left(\lambda_{2}-\lambda_{1}\right)} \)
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