If specific resistance of a potentiometer wire is \( \mathrm{P} \) \( 10^{-7} \Omega \mathrm{m} ...
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0If specific resistance of a potentiometer wire is
\( \mathrm{P} \) \( 10^{-7} \Omega \mathrm{m} \) and current flow through it is \( 0.1 \mathrm{~A} \),
W cross-sectional area of wire is \( 10^{-6} \mathrm{~m}^{2} \) then potential gradient will be :-
(1) \( 10^{-2} \mathrm{volt} / \mathrm{m} \)
(2) \( 10^{-4} \mathrm{volt} / \mathrm{m} \)
(3) \( 10^{-6} \mathrm{volt} / \mathrm{m} \)
(4) \( 10^{-8} \) volt \( / \mathrm{m} \)
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