If \( (\sqrt{3}) b x+a y=2 a b \) touches the ellipse \( \frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}....

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If \( (\sqrt{3}) b x+a y=2 a b \) touches the ellipse
\( \mathrm{P} \)
\( \frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1 \), then the eccentric angle of the point of contact is
(1) \( \frac{\pi}{6} \)
(2) \( \frac{\pi}{4} \)
(3) \( \frac{\pi}{3} \)
(4) \( \frac{\pi}{2} \)
.


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