If \( \tan \alpha \) is equal to the integral solution of the inequality \( 4 x^{2}-16 x+150 \) ... VIDEO
If \( \tan \alpha \) is equal to the integral solution of the inequality \( 4 x^{2}-16 x+150 \) and \( \cos \beta \) is equal to the slope of the bisector of the first quadrant, then \( \sin (\alpha+\beta) \sin (\alpha-\beta) \) is equal to
(1) \( \frac{3}{5} \)
(2) \( \frac{3}{5} \)
(3) \( \frac{2}{\sqrt{5}} \)
(4) \( \frac{4}{5} \)
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