If the activation energy for the forward reaction is \( 150 \mathrm{~kJ} \) \( \mathrm{mol}^{-1}...

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If the activation energy for the forward reaction is \( 150 \mathrm{~kJ} \) \( \mathrm{mol}^{-1} \) and that of the reverse reaction is \( 260 \mathrm{~kJ} \mathrm{~mol}^{-1} \), what is the enthalpy change for the reaction ?
(a) \( 410 \mathrm{~kJ} \mathrm{~mol}^{-1} \)
(b) \( -110 \mathrm{~kJ} \mathrm{~mol}^{-1} \)
(c) \( 110 \mathrm{~kJ} \mathrm{~mol}^{-1} \)
(d) \( -410 \mathrm{~kJ} \mathrm{~mol}^{-1} \)
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