If the orbital velocity of the moon is \( 1020 \mathrm{~m} \mathrm{~s}^{-1} \), find the time ta... VIDEO
If the orbital velocity of the moon is \( 1020 \mathrm{~m} \mathrm{~s}^{-1} \), find the time taken by the moon to complete one revolution around the Earth. Explain why this period is different from the period that is observed from the Earth, which is \( 29.5 \) days.
(Take the distance of the moon from the Earth as
\( 3.4 \times 10^{8} \mathrm{~m} \), and \( \left.\frac{1}{86400}=1.157 \times 10^{-5}\right) \)
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