If the shortest distance between the straight lines \(3(x-1)=6(y-2)=2(z-1)\) and \(4(x-2)=2(y-\l.... VIDEO
If the shortest distance between the straight lines \(3(x-1)=6(y-2)=2(z-1)\) and \(4(x-2)=2(y-\lambda)=(z-3), \lambda \in R\) is \(\frac{1}{\sqrt{38}}\), then the integral value of \(\lambda\) is equal to: 📲PW App Link - https://bit.ly/YTAI_PWAP 🌐PW Website - https://www.pw.live
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