If the solution of \( \frac{x}{x^{2}+y^{2}} \quad \mathrm{~d} y=\left(\frac{y}{x^{2}+y^{2}}-1\ri...
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If the solution of \( \frac{x}{x^{2}+y^{2}} \quad \mathrm{~d} y=\left(\frac{y}{x^{2}+y^{2}}-1\right) \) \( \mathrm{d} x \) satisfies \( y(0)=1 \), then the value of \( \frac{16}{\pi} y(\pi / 4) \) is
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