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If the velocity of a particle is \( v=A t+B t^{2} \), where \( \mathrm{A} \)
P and \( B \) are constants, then the distance travelled by it

W between \( 1 \mathrm{~s} \) and \( 2 \mathrm{~s} \) is:
(1) \( \frac{3}{2} A+4 B \)
(2) \( 3 A+7 B \)
(3) \( \frac{3}{2} \mathrm{~A}+\frac{7}{3} \mathrm{~B} \)
(4) \( \frac{A}{2}+\frac{B}{3} \)
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