If \( \triangle A B C \) is right angled at \( C \), then the value of \( \cos (A+B) \) is
(a) 0... VIDEO
If \( \triangle A B C \) is right angled at \( C \), then the value of \( \cos (A+B) \) is
(a) 0
(b) 1
(c) \( \frac{1}{2} \)
(d) \( \frac{\sqrt{3}}{2} \)
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