If we express the energy of a photon in \( \mathrm{KeV} \) and the wavelength in angstroms, then...

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If we express the energy of a photon in \( \mathrm{KeV} \) and the wavelength in angstroms, then energy of a photon can be calculated from the relation
(A) \( E=12.4 h v \)
(B) \( E=12.4 h / \lambda \)
(C) \( E=12.4 / \lambda \)
(D) \( E=h v \)
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