If \(x+y=1\), then \(\sum_{k=0}^n k^{2 n} C_k \cdot x^k \cdot y^{n-k}=\)....

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If \(x+y=1\), then \(\sum_{k=0}^n k^{2 n} C_k \cdot x^k \cdot y^{n-k}=\) 📲PW App Link - https://bit.ly/YTAI_PWAP 🌐PW Website - https://www.pw.live



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