In a tight angled triangle the hypotenuse is \( 2 \sqrt{2} \) times the length of perpendicular ...

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In a tight angled triangle the hypotenuse is \( 2 \sqrt{2} \) times the length of perpendicular drawn from the opposite vertex on the hypotenuse, then the other two angles, are
(A) \( \frac{\pi}{3}, \frac{\pi}{6} \)
(B) \( \frac{\pi}{4}, \frac{\pi}{4} \)
(C) \( \frac{8}{8}, \frac{3 \pi}{8} \)
(D) \( \frac{\pi}{12}, \frac{5 \pi}{12} \)
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