In a \( \triangle A B C \), if \( a=(b-c) \sec \theta \), then \( \frac{2 \sqrt{b c}}{b-c} \sin ...
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0In a \( \triangle A B C \), if \( a=(b-c) \sec \theta \), then \( \frac{2 \sqrt{b c}}{b-c} \sin \frac{A}{2}= \)
(A) \( \cos \theta \)
(B) \( \cot \theta \)
(C) \( \tan \theta \)
(D) \( \sin \theta \)
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