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In given figure, \( \mathrm{X} \) and \( \mathrm{Y} \) are two long straight parallel conductors each carrying a current of \( 2 \mathrm{~A} \). The force on each conductor is \( \mathrm{F} \) newtons. When the current in each is changed to \( 1 \mathrm{~A} \) and reversed in direction, the force on each is now
(A) \( \mathrm{F} / 4 \) and unchanged in direction
(B) \( F / 2 \) and reversed in direction
\begin{tabular}{l} \( \stackrel{X}{P A} \) \\ \hline\( \vec{A} A \) \\ \hline\( \vec{Y} \) \end{tabular}
\( \mathrm{P} \)
(C) \( F / 2 \) and unchanged in direction
(D) \( F / 4 \) and reversed in direction
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