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In the circuit in figure \( \mathrm{L}=10 \mathrm{H}, \mathrm{R}=5 \Omega \),
P \( \mathrm{E}=15 \mathrm{~V} \). The switch \( \mathrm{S} \) is closed at \( \mathrm{t}=0 \). At \( t=2 \mathrm{~s} \), the current in the circuit is
W
(1) \( 3\left(1-\frac{1}{e}\right) A \)
(2) \( 3\left(1-\frac{1}{e^{2}}\right) A \)
(3) \( 3\left(\frac{1}{e}\right) A \)
(4) \( 3\left(\frac{1}{e^{2}}\right) A \)
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