Duration: 5:06

14 views

0

In the circuit shown in the figure, there are two parallel plate capacitors each of capacitance \( \mathrm{C} \). The switch \( \mathrm{S}_{1} \) is pressed first to fully charge the capacitor \( \mathrm{C}_{1} \) and then released The switch \( \mathrm{S}_{2} \) is then pressed to charge the capacitor \( \mathrm{C}_{2} \). After some time, \( \mathrm{S}_{2} \) is released and then \( \mathrm{S}_{3} \) is pressed. After some time,
\( \mathrm{P} \)
- (A) the charge on the upper plate of \( \mathrm{C}_{1} \) is \( 2 \mathrm{CV}_{0} \)
(B) the charge on the upper plate of \( \mathrm{C}_{1} \) is \( \mathrm{CV}_{0} \)
(C) the charge on the upper plate of \( \mathrm{C}_{2} \) is 0 .
W
- (D) the charge on the upper plate of \( \mathrm{C}_{2} \) is \( -\mathrm{CV}_{0} \)
📲PW App Link - https://bit.ly/YTAI_PWAP
🌐PW Website - https://www.pw.live