\( \int e^{-x}(1-\tan x) \sec x d x \) is equal to (A) \( e^{-x} \sec x+c \) (B) \( e^{-x} \tan ...
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\( \int e^{-x}(1-\tan x) \sec x d x \) is equal to
(A) \( e^{-x} \sec x+c \)
(B) \( e^{-x} \tan x+c \)
(C) \( -e^{-x} \tan x+c \)
(D) \( -e^{-x} \sec x+c \)
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