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Let \( a_{1}, a_{2}, a_{3}, \ldots \). be terms of an A.P. If \( \frac{a_{1}+a_{2}+\ldots+a_{p}}{a_{1}+a_{2}+\ldots+a_{q}}=\frac{p^{2}}{q^{2}}, p \neq q \) then \( \frac{a_{6}}{a_{21}} \) equals
(1) \( \frac{7}{2} \)
(2) \( \frac{2}{7} \)
(3) \( \frac{11}{41} \)
(4) \( \frac{41}{11} \)
\( \mathrm{P} \)
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